What is the solution for (dr)/(dθ)=10-6r ?

The solution for (dr)/(dθ)=10-6r is r(θ)=-(e^{-6θ-c_{1}})/3+5/3

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(dr)/(dθ)=10-6r

\frac{d r}{d θ} = 10 - 6 r

r (θ) = - \frac{e ^{- 6 θ - c_{1}}}{3} + \frac{5}{3}

Solution steps

\frac{d r}{d θ} = 10 - 6 r

Solve separable ODE:

r (θ) = - \frac{e ^{- 6 θ - c_{1}}}{3} + \frac{5}{3}

r (θ) = - \frac{e ^{- 6 θ - c_{1}}}{3} + \frac{5}{3}

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f (x) = ln (- x)

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What is the solution for (dr)/(dθ)=10-6r ?
The solution for (dr)/(dθ)=10-6r is r(θ)=-(e^{-6θ-c_{1}})/3+5/3