What is the solution for (dy)/(dx)=e^{3x-2y} ?

The solution for (dy)/(dx)=e^{3x-2y} is y=(ln(2/3 e^{3x}+c_{1}))/2

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(dy)/(dx)=e^{3x-2y}

\frac{d y}{d x} = e^{3 x - 2 y}

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

Solution steps

\frac{d y}{d x} = e^{3 x - 2 y}

Solve separable ODE:

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

y = \frac{ln ( \frac{2}{3} e ^{3 x} + c _{1} )}{2}

\frac{d}{d x} (f (x) - 4 x + 1)

n = 1 \sum \infty (\frac{10}{11})^{n}

f (x) = - x - \frac{1}{x}

\frac{d}{d x} (e^{(x - 1)})

\frac{d}{d x} (\frac{8 x ^{2} - 40 x + 32}{3 x ^{\frac{1}{3}}})

What is the solution for (dy)/(dx)=e^{3x-2y} ?
The solution for (dy)/(dx)=e^{3x-2y} is y=(ln(2/3 e^{3x}+c_{1}))/2