What is the derivative of f(x)=-x-1/x ?

The derivative of f(x)=-x-1/x is -1+1/(x^2)

What is the first derivative of f(x)=-x-1/x ?

The first derivative of f(x)=-x-1/x is -1+1/(x^2)

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derivative of

f (x) = - x - \frac{1}{x}

- 1 + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (- x - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} - \frac{d}{d x} (\frac{1}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - 1 - (- \frac{1}{x ^{2}})

Simplify

= - 1 + \frac{1}{x ^{2}}

\frac{d}{d x} (e^{(x - 1)})

\frac{d}{d x} (\frac{8 x ^{2} - 40 x + 32}{3 x ^{\frac{1}{3}}})

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + 2 x - 15})

\int 5 x sin^{2} (x) d x

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

What is the derivative of f(x)=-x-1/x ?
The derivative of f(x)=-x-1/x is -1+1/(x^2)
What is the first derivative of f(x)=-x-1/x ?
The first derivative of f(x)=-x-1/x is -1+1/(x^2)