What is (\partial)/(\partial x)(sin(2x)cos(2y)) ?

The answer to (\partial)/(\partial x)(sin(2x)cos(2y)) is cos(2y)cos(2x)*2

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(\partial)/(\partial x)(sin(2x)cos(2y))

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

cos (2 y) cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x) cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 y) \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (2 y) cos (2 x) \cdot 2

\frac{x ^{2}}{1 - x ^{2}}

\int 15 x^{\frac{1}{2}} d x

\int_{- 2}^{2} x^{2} + 3 x - 4 d x

y^{^{'}} - \frac{6}{x} y = \frac{y ^{4}}{x ^{7}}

\int 4 x^{3} (7 x^{4} + 12)^{3} d x

What is (\partial)/(\partial x)(sin(2x)cos(2y)) ?
The answer to (\partial)/(\partial x)(sin(2x)cos(2y)) is cos(2y)cos(2x)*2