What is the solution for y^'-6/x y=(y^4)/(x^7) ?

The solution for y^'-6/x y=(y^4)/(x^7) is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-x^{12)+c_{1}}}

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y^'-6/x y=(y^4)/(x^7)

y^{^{'}} - \frac{6}{x} y = \frac{y ^{4}}{x ^{7}}

Solution steps

y^{'} (x) - \frac{6}{x} y = \frac{y ^{4}}{x ^{7}}

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What is the solution for y^'-6/x y=(y^4)/(x^7) ?
The solution for y^'-6/x y=(y^4)/(x^7) is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-x^{12)+c_{1}}}