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Popular >

area y=x^4-2x^3,y=0

Solution

area

y = x^{4} - 2 x^{3}, y = 0

Solution

\frac{8}{5}

+1

Decimal Notation

1.6

Solution steps

Apply the area formula:

\int_{0}^{2} x^{4} - 2 x^{3} d x

Solve

\int_{0}^{2} x^{4} - 2 x^{3} d x : \frac{8}{5}

The area is:

= \frac{8}{5}

Popular Examples

integral of e^{-x}e^x

\int e^{- x} e^{x} d x

integral from 0 to infinity of e^{-st}t

\int_{0}^{\infty} e^{- s t} t d t

integral of (1+x)sqrt(x)

\int (1 + x) x d x

tangent of f(x)=9e^xcos(x),(0,9)tangent of

f (x) = 9 e^{x} cos (x), (0, 9)

y^{^{''}} + y = x^{3}

Frequently Asked Questions (FAQ)

What is area y=x^4-2x^3,y=0 ?
The answer to area y=x^4-2x^3,y=0 is 8/5