What is the first derivative of 3x^2+6 ?

The first derivative of 3x^2+6 is 6x

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derivative of 3x^2+6

\frac{d}{d x} (3 x^{2} + 6)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6) = 0

= 6 x + 0

Simplify

= 6 x

\frac{d}{d x} (1 - (\frac{a}{x})^{b - 1})

x \to 0 lim (4 e^{x})

x^{11} arccot (x)

t \to (0) lim (ln (t))

y^{^{'}} = \frac{2 - 3 y}{200 + x}