What is (\partial)/(\partial s)(rsin(t)sin(s)) ?

The answer to (\partial)/(\partial s)(rsin(t)sin(s)) is rsin(t)cos(s)

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(\partial)/(\partial s)(rsin(t)sin(s))

\frac{\partial}{\partial s} (r sin (t) sin (s))

r sin (t) cos (s)

Solution steps

\frac{\partial}{\partial s} (r sin (t) sin (s))

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r sin (t) \frac{\partial}{\partial s} (sin (s))

Apply the common derivative:

\frac{\partial}{\partial s} (sin (s)) = cos (s)

= r sin (t) cos (s)

\frac{\partial}{\partial x} (\frac{4 x - y}{4 x + y})

\frac{d y}{d x} = y^{- 1} x^{- 3}

y^{^{'}} = \frac{6 y ^{2}}{x ^{2}}, y (- 2) = 5

\frac{d}{d x} (\frac{4}{3} tan (x))

x \to - 1 lim (13 + x)

What is (\partial)/(\partial s)(rsin(t)sin(s)) ?
The answer to (\partial)/(\partial s)(rsin(t)sin(s)) is rsin(t)cos(s)