What is the solution for yy^'=9cos(x) ?

The solution for yy^'=9cos(x) is y=sqrt(18sin(x)+c_{1)},y=-sqrt(18sin(x)+c_{1)}

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yy^'=9cos(x)

y y^{^{'}} = 9 cos (x)

y = 18 sin (x) + c_{1}, y = - 18 sin (x) + c_{1}

Solution steps

y y^{'} (x) = 9 cos (x)

Solve separable ODE:

y = 18 sin (x) + c_{1}, y = - 18 sin (x) + c_{1}

y = 18 sin (x) + c_{1}, y = - 18 sin (x) + c_{1}

\frac{d}{d x} (\frac{x}{12} - \frac{12}{x})

\frac{\partial}{\partial x} ((3 x + 6 y)^{10})

\int \frac{sin ( 2 x )}{23 + cos ^{2} ( x )} d x

\frac{d}{d x} ((\frac{1}{x - 3})^{2})

f (x) = x - 2 cos (x)

What is the solution for yy^'=9cos(x) ?
The solution for yy^'=9cos(x) is y=sqrt(18sin(x)+c_{1)},y=-sqrt(18sin(x)+c_{1)}