What is the tangent of y=5ln(x),\at x=1 ?

The tangent of y=5ln(x),\at x=1 is y=5x-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=5ln(x),\at x=1

tangent of

y = 5 ln (x), at x = 1

y = 5 x - 5

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

y = 5 ln (x) : \frac{d y}{d x} = \frac{5}{x}

Compute the slope of

y = 5 ln (x)

x = 1 : m = 5

Find the line with slope m=

5

and passing through

(1, 0) : y = 5 x - 5

y = 5 x - 5

y^{^{''}} = 2 y

x^{2} - 5 x

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{1 + e}

\int 1 + x d x

\int x^{5} (1 + x^{3})^{\frac{3}{2}} d x

What is the tangent of y=5ln(x),\at x=1 ?
The tangent of y=5ln(x),\at x=1 is y=5x-5