What is (\partial)/(\partial y)(9e^xln(y)) ?

The answer to (\partial)/(\partial y)(9e^xln(y)) is (9e^x)/y

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(\partial)/(\partial y)(9e^xln(y))

\frac{\partial}{\partial y} (9 e^{x} ln (y))

\frac{9 e ^{x}}{y}

Solution steps

\frac{\partial}{\partial y} (9 e^{x} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 e^{x} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 9 e^{x} \frac{1}{y}

Simplify

9 e^{x} \frac{1}{y} : \frac{9 e ^{x}}{y}

= \frac{9 e ^{x}}{y}

\frac{d}{d x} (\frac{5 x ^{2} - x ^{4}}{9})

n = 1 \sum \infty 1 + \frac{1}{n}

2^{70}

\int (x^{2} + 1)^{5} d x

\int + \frac{cos ( 3 x )}{1 + sin ^{2} ( 3 x )} d x

What is (\partial)/(\partial y)(9e^xln(y)) ?
The answer to (\partial)/(\partial y)(9e^xln(y)) is (9e^x)/y