What is the derivative of (5x^2-x^4/9) ?

The derivative of (5x^2-x^4/9) is 1/9 (10x-4x^3)

What is the first derivative of (5x^2-x^4/9) ?

The first derivative of (5x^2-x^4/9) is 1/9 (10x-4x^3)

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\frac{d}{d x} (\frac{5 x ^{2} - x ^{4}}{9})

\frac{1}{9} (10 x - 4 x^{3})

Solution steps

\frac{d}{d x} (\frac{5 x ^{2} - x ^{4}}{9})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9} \frac{d}{d x} (5 x^{2} - x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{9} (\frac{d}{d x} (5 x^{2}) - \frac{d}{d x} (x^{4}))

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (x^{4}) = 4 x^{3}

= \frac{1}{9} (10 x - 4 x^{3})

n = 1 \sum \infty 1 + \frac{1}{n}

2^{70}

\int (x^{2} + 1)^{5} d x

\int + \frac{cos ( 3 x )}{1 + sin ^{2} ( 3 x )} d x

\frac{d}{d x} (sin (3 x - 2))

What is the derivative of (5x^2-x^4/9) ?
The derivative of (5x^2-x^4/9) is 1/9 (10x-4x^3)
What is the first derivative of (5x^2-x^4/9) ?
The first derivative of (5x^2-x^4/9) is 1/9 (10x-4x^3)