What is (\partial)/(\partial x)(sin(-3x+1y+z)) ?

The answer to (\partial)/(\partial x)(sin(-3x+1y+z)) is -3cos(-3x+y+z)

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(\partial)/(\partial x)(sin(-3x+1y+z))

\frac{\partial}{\partial x} (sin (- 3 x + 1 y + z))

- 3 cos (- 3 x + y + z)

Solution steps

\frac{\partial}{\partial x} (sin (- 3 x + 1 \cdot y + z))

Simplify

sin (- 3 x + 1 \cdot y + z) : sin (- 3 x + y + z)

= \frac{\partial}{\partial x} (sin (- 3 x + y + z))

Treat

y, z

as constants

Apply the chain rule:

cos (- 3 x + y + z) \frac{\partial}{\partial x} (- 3 x + y + z)

= cos (- 3 x + y + z) \frac{\partial}{\partial x} (- 3 x + y + z)

\frac{\partial}{\partial x} (- 3 x + y + z) = - 3

= cos (- 3 x + y + z) (- 3)

Simplify

= - 3 cos (- 3 x + y + z)

\int (\frac{2 x ^{5} - 4 x + 8 x}{x}) d x

x \to + 0 lim (x \cdot + \frac{1}{x})

\frac{d}{d x} (e^{c o s h (2 x)})

x \to 1 + lim (f (x))

\frac{ln ( cos ( 2 x ) )}{5 x}

What is (\partial)/(\partial x)(sin(-3x+1y+z)) ?
The answer to (\partial)/(\partial x)(sin(-3x+1y+z)) is -3cos(-3x+y+z)