What is the tangent of f(x)= 2/(x+4),\at x=-3 ?

The tangent of f(x)= 2/(x+4),\at x=-3 is y=-2x-4

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tangent of f(x)= 2/(x+4),\at x=-3

tangent of

f (x) = \frac{2}{x + 4}, at x = - 3

y = - 2 x - 4

Solution steps

Find the tangent point:

(- 3, 2)

Find the slope of

f (x) = \frac{2}{x + 4} : \frac{df ( x )}{d x} = - \frac{2}{( x + 4 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x + 4}

x = - 3 : m = - 2

Find the line with slope m=

- 2

and passing through

(- 3, 2) : y = - 2 x - 4

y = - 2 x - 4

\frac{d}{d x} (\frac{3}{x ^{2} - 2})

\int_{0}^{2 π} 2

\frac{20}{( s - 4 ) ( s ^{2} + 4 )}

\frac{\partial}{\partial x} ((e^{x} - x) sin (y))

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}, y (1) = 2

What is the tangent of f(x)= 2/(x+4),\at x=-3 ?
The tangent of f(x)= 2/(x+4),\at x=-3 is y=-2x-4