What is the integral of e^{xy^2} ?

The integral of e^{xy^2} is 1/(y^2)e^{y^2x}+C

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integral of e^{xy^2}

\int e^{x y^{2}} d x

\frac{1}{y ^{2}} e^{y^{2} x} + C

Solution steps

\int e^{x y^{2}} d x

Apply u-substitution

: \int \frac{e ^{u}}{y ^{2}} d u

= \int \frac{e ^{u}}{y ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{y ^{2}} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{y ^{2}} e^{u}

Substitute back

u = y^{2} x

= \frac{1}{y ^{2}} e^{y^{2} x}

Add a constant to the solution

= \frac{1}{y ^{2}} e^{y^{2} x} + C

y = (x - 5)^{2} + 8

\int cos^{3} (3 x) sin^{4} (3 x) d x

\frac{\partial}{\partial x} (x^{3} - 3 x + y - e^{y})

\frac{d ^{4}}{d x ^{4}} (8 x)

\frac{\partial}{\partial x} (\frac{3 x - 2 y}{5 x + y})

What is the integral of e^{xy^2} ?
The integral of e^{xy^2} is 1/(y^2)e^{y^2x}+C