What is the derivative of y=(x-5)^2+8 ?

The derivative of y=(x-5)^2+8 is 2x-10

What is the first derivative of y=(x-5)^2+8 ?

The first derivative of y=(x-5)^2+8 is 2x-10

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derivative of

y = (x - 5)^{2} + 8

2 x - 10

Solution steps

\frac{d}{d x} ((x - 5)^{2} + 8)

Simplify

(x - 5)^{2} + 8 : x^{2} - 10 x + 33

= \frac{d}{d x} (x^{2} - 10 x + 33)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (10 x) + \frac{d}{d x} (33)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (10 x) = 10

\frac{d}{d x} (33) = 0

= 2 x - 10 + 0

Simplify

= 2 x - 10

\int cos^{3} (3 x) sin^{4} (3 x) d x

\frac{\partial}{\partial x} (x^{3} - 3 x + y - e^{y})

\frac{d ^{4}}{d x ^{4}} (8 x)

\frac{\partial}{\partial x} (\frac{3 x - 2 y}{5 x + y})

\frac{d}{d x} (- sin (x) - cos (x))

What is the derivative of y=(x-5)^2+8 ?
The derivative of y=(x-5)^2+8 is 2x-10
What is the first derivative of y=(x-5)^2+8 ?
The first derivative of y=(x-5)^2+8 is 2x-10