What is the derivative of-sin(x-cos(x)) ?

The derivative of-sin(x-cos(x)) is -cos(x)+sin(x)

What is the first derivative of-sin(x-cos(x)) ?

The first derivative of-sin(x-cos(x)) is -cos(x)+sin(x)

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\frac{d}{d x} (- sin (x) - cos (x))

- cos (x) + sin (x)

Solution steps

\frac{d}{d x} (- sin (x) - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (x)) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (cos (x)) = - sin (x)

= - cos (x) - (- sin (x))

Simplify

= - cos (x) + sin (x)

\frac{d}{d x} (- 2 x^{2} y)

y^{^{'}} = y (x y^{4} + 1)

\int \frac{x + 1}{9 - x ^{2}} d x

\int 7 sin (ln (x)) d x

x \to 0 lim (\frac{1}{1 + x})

What is the derivative of-sin(x-cos(x)) ?
The derivative of-sin(x-cos(x)) is -cos(x)+sin(x)
What is the first derivative of-sin(x-cos(x)) ?
The first derivative of-sin(x-cos(x)) is -cos(x)+sin(x)