What is the sum from n=1 to infinity of 5^n ?

The sum from n=1 to infinity of 5^n is diverges

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sum from n=1 to infinity of 5^n

n = 1 \sum \infty 5^{n}

diverges

Solution steps

n = 1 \sum \infty 5^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty 5^{n} - 5^{0}

n = 0 \sum \infty 5^{n} =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{\partial}{\partial x} (y + x)

x \to \infty lim (\frac{1 - 0. 8 ^{x + 1}}{1 - 0.8})

\frac{3}{( s - 3 )}

\frac{\partial}{\partial y} ((x + 2 y^{3})^{\frac{1}{3}})

\int_{0}^{l n (3)} x e^{x} d x

What is the sum from n=1 to infinity of 5^n ?
The sum from n=1 to infinity of 5^n is diverges