What is inverse oflaplace 3/((s-3)) ?

The answer to inverse oflaplace 3/((s-3)) is 3e^{3t}

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inverse oflaplace 3/((s-3))

inverse laplace

\frac{3}{( s - 3 )}

3 e^{3 t}

Solution steps

L^{- 1} {\frac{3}{( s - 3 )}}

= L^{- 1} {3 \cdot \frac{1}{s - 3}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {\frac{1}{s - 3}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 3}} = e^{3 t}

= 3 e^{3 t}

\frac{\partial}{\partial y} ((x + 2 y^{3})^{\frac{1}{3}})

\int_{0}^{l n (3)} x e^{x} d x

f (x) = - 2 x e^{- x^{2}}

\int \frac{1}{( y - 1 ) ^{2}} d y

z \to 2 πi lim (e^{z} - e^{- z})

What is inverse oflaplace 3/((s-3)) ?
The answer to inverse oflaplace 3/((s-3)) is 3e^{3t}