What is the limit as t approaches 2 of (2t)/(4-t^2) ?

The limit as t approaches 2 of (2t)/(4-t^2) is diverges

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limit as t approaches 2 of (2t)/(4-t^2)

t \to 2 lim (\frac{2 t}{4 - t ^{2}})

diverges

Solution steps

t \to 2 lim (\frac{2 t}{4 - t ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 2 + lim (\frac{2 t}{4 - t ^{2}}) = - \infty

t \to 2 - lim (\frac{2 t}{4 - t ^{2}}) = \infty

= diverges

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\frac{d}{d x} (\frac{7 - x e ^{x}}{x + e ^{x}})

\frac{( s - 1 )}{2 s ^{2} + 8 s + 11}

\int \frac{e ^{x - 5} - e ^{3 + x}}{e ^{1 - x}} d x

What is the limit as t approaches 2 of (2t)/(4-t^2) ?
The limit as t approaches 2 of (2t)/(4-t^2) is diverges