What is the limit as x approaches 0 of (-3x+1)^{5/x} ?

The limit as x approaches 0 of (-3x+1)^{5/x} is 1/(e^{15)}

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limit as x approaches 0 of (-3x+1)^{5/x}

x \to 0 lim ((- 3 x + 1)^{\frac{5}{x}})

\frac{1}{e ^{15}}

Decimal Notation

3.05902 E - 7

Solution steps

x \to 0 lim ((- 3 x + 1)^{\frac{5}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{5}{x} l n (- 3 x + 1)})

Apply the Limit Chain Rule:

\frac{1}{e ^{15}}

= \frac{1}{e ^{15}}

\int (x + 2)^{13} d x

f (x) = x^{2} - 3 x

\frac{d}{d x} (\frac{x - 7 x x}{x})

f (x) = 5 x^{2} cos (x) + x

f (x) = e^{x} + x e^{x}

What is the limit as x approaches 0 of (-3x+1)^{5/x} ?
The limit as x approaches 0 of (-3x+1)^{5/x} is 1/(e^{15)}