What is the tangent of ((x^2))/(x-7) ?

The tangent of ((x^2))/(x-7) is y=(a_{0}^2-14a_{0})/((a_{0)-7)^2}x+(7a_{0}^2)/((a_{0)-7)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of ((x^2))/(x-7)

tangent of

\frac{( x ^{2} )}{x - 7}

y = \frac{a _{0}^{2} - 14 a _{0}}{( a _{0} - 7 ) ^{2}} x + \frac{7 a _{0}^{2}}{( a _{0} - 7 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{a _{0}^{2}}{a _{0} - 7})

Find the slope of

y = \frac{x ^{2}}{x - 7} : \frac{d y}{d x} = \frac{x ^{2} - 14 x}{( x - 7 ) ^{2}}

Compute the slope of

y = \frac{x ^{2}}{x - 7}

x = a_{0} : m = \frac{a _{0}^{2} - 14 a _{0}}{( a _{0} - 7 ) ^{2}}

Find the line with slope m=

\frac{a _{0}^{2} - 14 a _{0}}{( a _{0} - 7 ) ^{2}}

and passing through

(a_{0}, \frac{a _{0}^{2}}{a _{0} - 7}) : y = \frac{a _{0}^{2} - 14 a _{0}}{( a _{0} - 7 ) ^{2}} x + \frac{7 a _{0}^{2}}{( a _{0} - 7 ) ^{2}}

y = \frac{a _{0}^{2} - 14 a _{0}}{( a _{0} - 7 ) ^{2}} x + \frac{7 a _{0}^{2}}{( a _{0} - 7 ) ^{2}}

\frac{x}{x ^{4} + 1}

\frac{\partial}{\partial u} (4 u cos (v))

\int 2 x^{2} - 2 x^{- 1} d x

\frac{\partial}{\partial y} (6 x y - 12)

\frac{\partial}{\partial x} (2 x^{2} + 3 x y)

What is the tangent of ((x^2))/(x-7) ?
The tangent of ((x^2))/(x-7) is y=(a_{0}^2-14a_{0})/((a_{0)-7)^2}x+(7a_{0}^2)/((a_{0)-7)^2}