What is the integral of (-x)/((x+1)-sqrt(x+1)) ?

The integral of (-x)/((x+1)-sqrt(x+1)) is -x-1-2sqrt(x+1)+C

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integral of (-x)/((x+1)-sqrt(x+1))

\int \frac{- x}{( x + 1 ) - x + 1} d x

- x - 1 - 2 x + 1 + C

Solution steps

\int \frac{- x}{x + 1 - x + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{x}{x + 1 - x + 1} d x

Apply u-substitution

: \int 2 (u + 1) d u

= - \int 2 (u + 1) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int u + 1 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - 2 (\int u d u + \int 1 d u)

\int u d u = \frac{u ^{2}}{2}

\int 1 d u = u

= - 2 (\frac{u ^{2}}{2} + u)

Substitute back

u = x + 1

= - 2 (\frac{( x + 1 ) ^{2}}{2} + x + 1)

Simplify

- 2 (\frac{( x + 1 ) ^{2}}{2} + x + 1) : - x - 1 - 2 x + 1

= - x - 1 - 2 x + 1

Add a constant to the solution

= - x - 1 - 2 x + 1 + C

y = x^{2} - 8 x - 6

\frac{d y}{d x} = x e^{6 x - 5 y}

\frac{\partial}{\partial y} (e^{2 x})

\frac{d}{d x} (\frac{2 x - x ^{2}}{x})

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 40 cos (8 t)

What is the integral of (-x)/((x+1)-sqrt(x+1)) ?
The integral of (-x)/((x+1)-sqrt(x+1)) is -x-1-2sqrt(x+1)+C