What is the solution for (6x+1)y^2(dy)/(dx)+3x^2+2y^3=0 ?

The solution for (6x+1)y^2(dy)/(dx)+3x^2+2y^3=0 is y=\sqrt[3]{-(3x^3)/(6x+1)+(c_{1})/(6x+1)}

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(6x+1)y^2(dy)/(dx)+3x^2+2y^3=0

(6 x + 1) y^{2} \frac{d y}{d x} + 3 x^{2} + 2 y^{3} = 0

Solution steps

(6 x + 1) y^{2} \frac{d y}{d x} + 3 x^{2} + 2 y^{3} = 0

Solve Bernoulli ODE:

x \to - 1 + lim (3 x + 3 - 5)

y = cos (3 x^{2})

x \to 3 + lim (\frac{3 x + 4}{x - 3})

\frac{\partial}{\partial x} (\frac{( x + y )}{( 1 + x ^{2} )})

(e^{x} - 1)^{^{'}}

What is the solution for (6x+1)y^2(dy)/(dx)+3x^2+2y^3=0 ?
The solution for (6x+1)y^2(dy)/(dx)+3x^2+2y^3=0 is y=\sqrt[3]{-(3x^3)/(6x+1)+(c_{1})/(6x+1)}