What is the derivative of y=cos(3x^2) ?

The derivative of y=cos(3x^2) is -sin(3x^2)*6x

What is the first derivative of y=cos(3x^2) ?

The first derivative of y=cos(3x^2) is -sin(3x^2)*6x

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derivative of

y = cos (3 x^{2})

- sin (3 x^{2}) \cdot 6 x

Solution steps

\frac{d}{d x} (cos (3 x^{2}))

Apply the chain rule:

- sin (3 x^{2}) \frac{d}{d x} (3 x^{2})

= - sin (3 x^{2}) \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

= - sin (3 x^{2}) \cdot 6 x

x \to 3 + lim (\frac{3 x + 4}{x - 3})

\frac{\partial}{\partial x} (\frac{( x + y )}{( 1 + x ^{2} )})

(e^{x} - 1)^{^{'}}

x e^{\frac{x}{2}}

d cos (t) + t^{2} sin (t)

What is the derivative of y=cos(3x^2) ?
The derivative of y=cos(3x^2) is -sin(3x^2)*6x
What is the first derivative of y=cos(3x^2) ?
The first derivative of y=cos(3x^2) is -sin(3x^2)*6x