What is the derivative of y=sqrt(3x-7) ?

The derivative of y=sqrt(3x-7) is 3/(2sqrt(3x-7))

What is the first derivative of y=sqrt(3x-7) ?

The first derivative of y=sqrt(3x-7) is 3/(2sqrt(3x-7))

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derivative of

y = 3 x - 7

\frac{3}{2 3 x - 7}

Solution steps

\frac{d}{d x} (3 x - 7)

Apply the chain rule:

\frac{1}{2 3 x - 7} \frac{d}{d x} (3 x - 7)

= \frac{1}{2 3 x - 7} \frac{d}{d x} (3 x - 7)

\frac{d}{d x} (3 x - 7) = 3

= \frac{1}{2 3 x - 7} \cdot 3

Simplify

\frac{1}{2 3 x - 7} \cdot 3 : \frac{3}{2 3 x - 7}

= \frac{3}{2 3 x - 7}

\int_{0}^{1} (x^{2} - 2 x + 3) d x

\int_{0}^{\frac{1}{2}} 7 arccos (x) d x

\frac{\partial}{\partial y} (1 - x y cos (π y))

- ln (1 - x)

x \to - \infty lim (\frac{x}{2})

What is the derivative of y=sqrt(3x-7) ?
The derivative of y=sqrt(3x-7) is 3/(2sqrt(3x-7))
What is the first derivative of y=sqrt(3x-7) ?
The first derivative of y=sqrt(3x-7) is 3/(2sqrt(3x-7))