What is the tangent of y=(5x)/(x+3),(2,2) ?

The tangent of y=(5x)/(x+3),(2,2) is y= 3/5 x+4/5

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tangent of y=(5x)/(x+3),(2,2)

tangent of

y = \frac{5 x}{x + 3}, (2, 2)

y = \frac{3}{5} x + \frac{4}{5}

Solution steps

Find the slope of

y = \frac{5 x}{x + 3} : \frac{d y}{d x} = \frac{15}{( x + 3 ) ^{2}}

Compute the slope of

y = \frac{5 x}{x + 3}

(2, 2) : m = \frac{3}{5}

Find the line with slope m=

\frac{3}{5}

and passing through

(2, 2) : y = \frac{3}{5} x + \frac{4}{5}

y = \frac{3}{5} x + \frac{4}{5}

f (x) = (x - 6) (2 x + 1)

f (x) = 2 + cos (x), at x = \frac{π}{2}

\frac{d}{d x} (\frac{- 9}{x ^{2} + 81})

\frac{\partial}{\partial x} (x^{2} e^{- x})

\int \frac{1}{y ^{4} + 1} d y

What is the tangent of y=(5x)/(x+3),(2,2) ?
The tangent of y=(5x)/(x+3),(2,2) is y= 3/5 x+4/5