What is the derivative of t^4-8t ?

The derivative of t^4-8t is 4t^3-8

What is the first derivative of t^4-8t ?

The first derivative of t^4-8t is 4t^3-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

t^{4} - 8 t

4 t^{3} - 8

Solution steps

\frac{d}{d t} (t^{4} - 8 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{4}) - \frac{d}{d t} (8 t)

\frac{d}{d t} (t^{4}) = 4 t^{3}

\frac{d}{d t} (8 t) = 8

= 4 t^{3} - 8

- 9

\int cot (\frac{θ}{9}) d θ

x \to 0 lim (\frac{∣ x - 5 ∣}{x - 5})

\frac{- x ^{2} - 5}{( x ^{2} - 5 ) ^{2}}

y^{^{'}} + 4 y = 20, y (1) = 30

What is the derivative of t^4-8t ?
The derivative of t^4-8t is 4t^3-8
What is the first derivative of t^4-8t ?
The first derivative of t^4-8t is 4t^3-8