What is the derivative of f(x)=log_{4}(x) ?

The derivative of f(x)=log_{4}(x) is 1/(2ln(2)x)

What is the first derivative of f(x)=log_{4}(x) ?

The first derivative of f(x)=log_{4}(x) is 1/(2ln(2)x)

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derivative of

f (x) = lo g_{4} (x)

\frac{1}{2 ln ( 2 ) x}

Solution steps

\frac{d}{d x} (lo g_{4} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= \frac{1}{x ln ( 4 )}

Simplify

ln (4) : 2 ln (2)

= \frac{1}{2 ln ( 2 ) x}

x \to 0 lim (\frac{( x + h ) ^{- 2} - h ^{- 2}}{x})

\int (x^{2} + 4) e^{- x} d x

\frac{d x}{d y} = x - x^{2}

\int t (t - 2) d t

t^{2} e^{4 t}

What is the derivative of f(x)=log_{4}(x) ?
The derivative of f(x)=log_{4}(x) is 1/(2ln(2)x)
What is the first derivative of f(x)=log_{4}(x) ?
The first derivative of f(x)=log_{4}(x) is 1/(2ln(2)x)