What is derivative of f(t)=((x^2+12))/(sqrt(x)) ?

The answer to derivative of f(t)=((x^2+12))/(sqrt(x)) is (dx)/(dt)=0

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derivative of f(t)=((x^2+12))/(sqrt(x))

derivative of

f (t) = \frac{( x ^{2} + 12 )}{x}

\frac{d x}{d t} = 0

Solution steps

f (t) = \frac{x ^{2} + 12}{x}

Treat

x

x (t)

Differentiate both sides:

0 = \frac{3 \frac{d x}{d t} x ^{2} - 12 \frac{d x}{d t}}{2 x x}

Isolate

\frac{d x}{d t} : \frac{d x}{d t} = 0

\frac{d x}{d t} = 0

\frac{d}{d x} (2 tan (5 x) + e^{- 3 x})

\frac{d}{d x} (x^{2 - 3 x} x^{2})

i = 1 \sum \infty i

x \to - 7 lim (\frac{- x ^{2}}{x + 7})

\int \frac{1}{( x + 7 ) ^{2}} d x

What is derivative of f(t)=((x^2+12))/(sqrt(x)) ?
The answer to derivative of f(t)=((x^2+12))/(sqrt(x)) is (dx)/(dt)=0