What is inverse oflaplace-1 ?

The answer to inverse oflaplace-1 is -\delta(t)

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inverse oflaplace-1

inverse laplace

- 1

- δ (t)

Solution steps

L^{- 1} {- 1}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {1}

L^{- 1} {1} : δ (t)

= - δ (t)

\frac{d}{d x} (cos^{2} (e^{c o s^{2} (x)}))

\int ln (cos (x)) sin (x) d x

y^{^{'}} + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}

\int sin^{2} (3 x) \cdot cos^{4} (3 x) d x

\frac{d}{d x} (\frac{4 x + 1}{4 x - 1})