What is the derivative of x-2cos(x) ?

The derivative of x-2cos(x) is 1+2sin(x)

What is the first derivative of x-2cos(x) ?

The first derivative of x-2cos(x) is 1+2sin(x)

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\frac{d}{d x} (x - 2 cos (x))

1 + 2 sin (x)

Solution steps

\frac{d}{d x} (x - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2 cos (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 1 - (- 2 sin (x))

Simplify

= 1 + 2 sin (x)

x \to 2 + lim (e^{\frac{1}{2 - x}})

- 6 x^{2} + 9 x + 4 x^{3}

\frac{d}{d x} ((8 x + 1)^{2})

\int \frac{17}{( x + 1 ) ( x ^{2} + 16 )} d x

\int sec^{3} (θ) d θ

What is the derivative of x-2cos(x) ?
The derivative of x-2cos(x) is 1+2sin(x)
What is the first derivative of x-2cos(x) ?
The first derivative of x-2cos(x) is 1+2sin(x)