What is the limit as x approaches 2+of e^{1/(2-x)} ?

The limit as x approaches 2+of e^{1/(2-x)} is 0

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limit as x approaches 2+of e^{1/(2-x)}

x \to 2 + lim (e^{\frac{1}{2 - x}})

0

Solution steps

x \to 2 + lim (e^{\frac{1}{2 - x}})

Apply the Limit Chain Rule:

0

= 0

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\frac{d}{d x} ((8 x + 1)^{2})

\int \frac{17}{( x + 1 ) ( x ^{2} + 16 )} d x

\int sec^{3} (θ) d θ

\frac{\partial}{\partial x} (x^{3} - 2 x^{2} + y^{3} - 2 y)

What is the limit as x approaches 2+of e^{1/(2-x)} ?
The limit as x approaches 2+of e^{1/(2-x)} is 0