What is the sum from n=4 to infinity of (1/4)^n ?

The sum from n=4 to infinity of (1/4)^n is converges

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sum from n=4 to infinity of (1/4)^n

n = 4 \sum \infty (\frac{1}{4})^{n}

converges

Solution steps

n = 4 \sum \infty (\frac{1}{4})^{n}

Apply Series Ratio Test:

converges

= converges

\int \frac{2 x + 3}{( x - 3 ) ( x + 3 )} d x

\frac{\partial}{\partial x} (tan (y) e^{x})

x \to 1 lim (x^{2} - 2 x + 1)

n = 0 \sum \infty 6^{n + 1}

n = 0 \sum \infty (- 1)^{n} e^{- n}

What is the sum from n=4 to infinity of (1/4)^n ?
The sum from n=4 to infinity of (1/4)^n is converges