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Popular >

y^'=(xe^{x^2})/2

Solution

y^{^{'}} = \frac{x e ^{x^{2}}}{2}

Solution

y = \frac{1}{4} e^{x^{2}} + c_{1}

Solution steps

y^{'} (x) = \frac{x e ^{x^{2}}}{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{x e ^{x^{2}}}{2} d x

\int \frac{x e ^{x^{2}}}{2} d x = \frac{1}{4} e^{x^{2}} + c_{1}

y = \frac{1}{4} e^{x^{2}} + c_{1}

Popular Examples

(\partial)/(\partial x)(2x^{0.3}y^{0.3})

\frac{\partial}{\partial x} (2 x^{0.3} y^{0.3})

integral of r^2sec^2(r^3)

\int r^{2} sec^{2} (r^{3}) d r

tangent of-6+250x^3-3x^5 tangent of

- 6 + 250 x^{3} - 3 x^{5}

slope of y=7+4x^2-2x^3 slope

y = 7 + 4 x^{2} - 2 x^{3}

(d^2)/(dx^2)(x^3-3x)

\frac{d ^{2}}{d x ^{2}} (x^{3} - 3 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=(xe^{x^2})/2 ?
The solution for y^'=(xe^{x^2})/2 is y= 1/4 e^{x^2}+c_{1}