What is the integral of 2xsqrt(x-3) ?

The integral of 2xsqrt(x-3) is 2(2/5 (x-3)^{5/2}+2(x-3)^{3/2})+C

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integral of 2xsqrt(x-3)

\int 2 x x - 3 d x

2 (\frac{2}{5} (x - 3)^{\frac{5}{2}} + 2 (x - 3)^{\frac{3}{2}}) + C

Solution steps

\int 2 x x - 3 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x x - 3 d x

Apply u-substitution

: \int (u + 3) u d u

= 2 \cdot \int (u + 3) u d u

Expand

(u + 3) u : u^{\frac{3}{2}} + 3 u

= 2 \cdot \int u^{\frac{3}{2}} + 3 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{\frac{3}{2}} d u + \int 3 u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 3 u d u = 2 u^{\frac{3}{2}}

= 2 (\frac{2}{5} u^{\frac{5}{2}} + 2 u^{\frac{3}{2}})

Substitute back

u = x - 3

= 2 (\frac{2}{5} (x - 3)^{\frac{5}{2}} + 2 (x - 3)^{\frac{3}{2}})

Add a constant to the solution

= 2 (\frac{2}{5} (x - 3)^{\frac{5}{2}} + 2 (x - 3)^{\frac{3}{2}}) + C

\int \frac{1}{( y - 3 ) ( y - 2 ) ( y - 1 )} d y

\int \frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}} d x

x^{2} y^{^{''}} + 2 x y^{^{'}} - 12 y = 0, y (1) = 0, y^{^{'}} (1) = - 2

n = 1 \sum \infty \frac{1}{n ^{0}}

x \frac{d y}{d x} + 4 y = x^{3} - x

What is the integral of 2xsqrt(x-3) ?
The integral of 2xsqrt(x-3) is 2(2/5 (x-3)^{5/2}+2(x-3)^{3/2})+C