What is the solution for (dy)/(dx)=(4x^4-7x^2+6) ?

The solution for (dy)/(dx)=(4x^4-7x^2+6) is y=(4x^5)/5-(7x^3)/3+6x+c_{1}

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(dy)/(dx)=(4x^4-7x^2+6)

\frac{d y}{d x} = (4 x^{4} - 7 x^{2} + 6)

y = \frac{4 x ^{5}}{5} - \frac{7 x ^{3}}{3} + 6 x + c_{1}

Solution steps

\frac{d y}{d x} = (4 x^{4} - 7 x^{2} + 6)

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = (4 x^{4} - 7 x^{2} + 6)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 4 x^{4} - 7 x^{2} + 6 d x

\int 4 x^{4} - 7 x^{2} + 6 d x = \frac{4 x ^{5}}{5} - \frac{7 x ^{3}}{3} + 6 x + c_{1}

y = \frac{4 x ^{5}}{5} - \frac{7 x ^{3}}{3} + 6 x + c_{1}

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What is the solution for (dy)/(dx)=(4x^4-7x^2+6) ?
The solution for (dy)/(dx)=(4x^4-7x^2+6) is y=(4x^5)/5-(7x^3)/3+6x+c_{1}