What is the first derivative of x^2-1 ?

The first derivative of x^2-1 is 2x

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derivative of x^2-1

derivative of

x^{2} - 1

2 x

Solution steps

\frac{d}{d x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x - 0

Simplify

= 2 x

\frac{\partial}{\partial x} (- x y^{2} + x y)

\frac{d}{d x} (\frac{x}{x - 1})

x^{2} y^{^{'}} + 2 x y = 5 y^{4}

\frac{\partial}{\partial x} (x^{3} + 2^{y} + x^{y})

\frac{\partial}{\partial x} (5 x y^{5} z)