What is the derivative of (2x+5)^7 ?

The derivative of (2x+5)^7 is 14(2x+5)^6

What is the first derivative of (2x+5)^7 ?

The first derivative of (2x+5)^7 is 14(2x+5)^6

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derivative of

(2 x + 5)^{7}

14 (2 x + 5)^{6}

Solution steps

\frac{d}{d x} ((2 x + 5)^{7})

Apply the chain rule:

7 (2 x + 5)^{6} \frac{d}{d x} (2 x + 5)

= 7 (2 x + 5)^{6} \frac{d}{d x} (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

= 7 (2 x + 5)^{6} \cdot 2

Simplify

= 14 (2 x + 5)^{6}

\frac{\partial}{\partial x} (4 x^{2} - 2 y^{2})

\int sec (θ) d θ

(2 x + 1 + 6 y) d x + 3 d y = 0

\int 4 sin (x) - 1 + 8 x - 5 d x

n = 1 \sum \infty \frac{n !}{2 ^{n}}

What is the derivative of (2x+5)^7 ?
The derivative of (2x+5)^7 is 14(2x+5)^6
What is the first derivative of (2x+5)^7 ?
The first derivative of (2x+5)^7 is 14(2x+5)^6