What is the solution for f^'(x)=22x+ln(22x) ?

The solution for f^'(x)=22x+ln(22x) is f(x)=11x^2+xln(22x)-x+c_{1}

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f^'(x)=22x+ln(22x)

f^{^{'}} (x) = 22 x + ln (22 x)

f (x) = 11 x^{2} + x ln (22 x) - x + c_{1}

Solution steps

f^{'} (x) = 22 x + ln (22 x)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 22 x + ln (22 x) d x

\int 22 x + ln (22 x) d x = 11 x^{2} + x ln (22 x) - x + c_{1}

f (x) = 11 x^{2} + x ln (22 x) - x + c_{1}

\frac{s}{2 s + 4}

\frac{\partial}{\partial x} (\frac{5}{x y} + \frac{x}{y} + \frac{y}{x})

\frac{\partial}{\partial x} (8 + x ln (x y - 7))

\frac{d}{d x} (3^{\frac{x}{2}})

\frac{d}{d x} (x^{3} + x^{2} - 5 x)

What is the solution for f^'(x)=22x+ln(22x) ?
The solution for f^'(x)=22x+ln(22x) is f(x)=11x^2+xln(22x)-x+c_{1}