What is the derivative of x^3+x^2-5x ?

The derivative of x^3+x^2-5x is 3x^2+2x-5

What is the first derivative of x^3+x^2-5x ?

The first derivative of x^3+x^2-5x is 3x^2+2x-5

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\frac{d}{d x} (x^{3} + x^{2} - 5 x)

3 x^{2} + 2 x - 5

Solution steps

\frac{d}{d x} (x^{3} + x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

= 3 x^{2} + 2 x - 5

\int x \cdot e^{5 x} d x

\int (\frac{1}{x ^{2}} - 1) d x

x \to 0 lim (\frac{5 sin ( x )}{x})

\int (x - 1)^{2} (x - 2) (x - 4) d x

x^{2} - 7 x

What is the derivative of x^3+x^2-5x ?
The derivative of x^3+x^2-5x is 3x^2+2x-5
What is the first derivative of x^3+x^2-5x ?
The first derivative of x^3+x^2-5x is 3x^2+2x-5