What is implicit (dy)/(dx),1=(y/x) ?

The answer to implicit (dy)/(dx),1=(y/x) is (dy)/(dx)= y/x

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implicit (dy)/(dx),1=(y/x)

implicit derivative

\frac{d y}{d x}, 1 = (\frac{y}{x})

\frac{d y}{d x} = \frac{y}{x}

Solution steps

1 = \frac{y}{x}

Treat

y

y (x)

Differentiate both sides:

0 = \frac{x \frac{d y}{d x} - y}{x ^{2}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{y}{x}

\frac{d y}{d x} = \frac{y}{x}

f (x) = 8 cos (t)

x \to 16 lim (\frac{sin ( x )}{x})

x y^{^{'}} - 2 y = - 2 x^{2} + 2 x - 2

\int_{0}^{4} (2 x + 4) d x

(2 x^{2} + 1) 3 (x^{2} - 4) 2

What is implicit (dy)/(dx),1=(y/x) ?
The answer to implicit (dy)/(dx),1=(y/x) is (dy)/(dx)= y/x