What is maclaurin e^{(-x^2)/2} ?

The answer to maclaurin e^{(-x^2)/2} is 1-1/2 x^2+1/8 x^4-1/48 x^6+1/384 x^8+\ldots

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maclaurin e^{(-x^2)/2}

maclaurin

e^{\frac{- x ^{2}}{2}}

1 - \frac{1}{2} x^{2} + \frac{1}{8} x^{4} - \frac{1}{48} x^{6} + \frac{1}{384} x^{8} + \dots

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( e ^{\frac{- x ^{2}}{2}} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{\frac{- x ^{2}}{2}} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{\frac{- x ^{2}}{2}} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{0}{1 !} x + \frac{- 1}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{3}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{- 15}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{105}{8 !} x^{8} + \dots

Refine

= 1 - \frac{1}{2} x^{2} + \frac{1}{8} x^{4} - \frac{1}{48} x^{6} + \frac{1}{384} x^{8} + \dots

\int \frac{1}{x ( x ^{2} - 8 )} d x

f (x) = x (x + 1)^{\frac{1}{3}}

\frac{d x}{d t} = \frac{1}{x + t + 1}

(2, 1), (5, 7)

\int \frac{2 e ^{2 x}}{e ^{2 x} + 12 e ^{x} + 35} d x

What is maclaurin e^{(-x^2)/2} ?
The answer to maclaurin e^{(-x^2)/2} is 1-1/2 x^2+1/8 x^4-1/48 x^6+1/384 x^8+\ldots