What is the integral of (csc^2(x))/(cot^2(x)) ?

The integral of (csc^2(x))/(cot^2(x)) is tan(x)+C

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integral of (csc^2(x))/(cot^2(x))

\int \frac{csc ^{2} ( x )}{cot ^{2} ( x )} d x

tan (x) + C

Solution steps

\int \frac{csc ^{2} ( x )}{cot ^{2} ( x )} d x

Simplify

\frac{csc ^{2} ( x )}{cot ^{2} ( x )} : sec^{2} (x)

= \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\int_{0}^{2} \frac{e ^{x}}{1 + e ^{x}} d x

\frac{d y}{d x} = \frac{x + 1}{y}

30 y^{^{''}} - 19 y^{^{'}} - 5 y = 0

x \to 7 lim (\frac{4}{( x - 7 ) ^{2}})

\int tan (x^{3}) x^{2} d x

What is the integral of (csc^2(x))/(cot^2(x)) ?
The integral of (csc^2(x))/(cot^2(x)) is tan(x)+C