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Popular >

y^'+3xy^3=0,y(0)=1

Solution

y^{^{'}} + 3 x y^{3} = 0, y (0) = 1

Solution

y = \frac{1}{3 x ^{2} + 1}

Solution steps

y^{'} (x) + 3 x y^{3} = 0

Solve separable ODE:

y = \frac{1}{3 x ^{2} + 1}

y = \frac{1}{3 x ^{2} + 1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+3xy^3=0,y(0)=1 ?
The solution for y^'+3xy^3=0,y(0)=1 is y= 1/(sqrt(3x^2+1))