What is the tangent of f(x)=x^2-8,(-2,-4) ?

The tangent of f(x)=x^2-8,(-2,-4) is y=-4x-12

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tangent of f(x)=x^2-8,(-2,-4)

tangent of

f (x) = x^{2} - 8, (- 2, - 4)

y = - 4 x - 12

Solution steps

Find the slope of

f (x) = x^{2} - 8 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 8

(- 2, - 4) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, - 4) : y = - 4 x - 12

y = - 4 x - 12

\frac{4}{( s ^{4} + 4 )}

\int_{2}^{\infty} x e^{- 9 x} d x

x \to 4 lim (4 - x)

\frac{1}{x - 7}

\int \frac{7}{3 x} d x

What is the tangent of f(x)=x^2-8,(-2,-4) ?
The tangent of f(x)=x^2-8,(-2,-4) is y=-4x-12