What is the integral from 2 to infinity of xe^{-9x} ?

The integral from 2 to infinity of xe^{-9x} is (19)/(81e^{18)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of xe^{-9x}

\int_{2}^{\infty} x e^{- 9 x} d x

\frac{19}{81 e ^{18}}

Decimal Notation

3.57246 E - 9

Solution steps

\int_{2}^{\infty} x e^{- 9 x} d x

Compute the indefinite integral:

\int x e^{- 9 x} d x = \frac{1}{81} (- 9 e^{- 9 x} x - e^{- 9 x}) + C

Compute the boundaries:

\int_{2}^{\infty} x e^{- 9 x} d x = 0 - (- \frac{19}{81 e ^{18}})

= 0 - (- \frac{19}{81 e ^{18}})

Simplify

= \frac{19}{81 e ^{18}}

x \to 4 lim (4 - x)

\frac{1}{x - 7}

\int \frac{7}{3 x} d x

\frac{\partial}{\partial t} (2 s^{2} + t^{2})

What is the integral from 2 to infinity of xe^{-9x} ?
The integral from 2 to infinity of xe^{-9x} is (19)/(81e^{18)}