What is the derivative of-0.5x^2+64x-25 ?

The derivative of-0.5x^2+64x-25 is -x+64

What is the first derivative of-0.5x^2+64x-25 ?

The first derivative of-0.5x^2+64x-25 is -x+64

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\frac{d}{d x} (- 0.5 x^{2} + 64 x - 25)

- x + 64

Solution steps

\frac{d}{d x} (- 0.5 x^{2} + 64 x - 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.5 x^{2}) + \frac{d}{d x} (64 x) - \frac{d}{d x} (25)

\frac{d}{d x} (0.5 x^{2}) = x

\frac{d}{d x} (64 x) = 64

\frac{d}{d x} (25) = 0

= - x + 64 - 0

Simplify

= - x + 64

y^{^{''}} + y = 3 sin (x)

y^{^{''}} + y^{^{'}} = 6 sin (2 x)

x \to 8 lim (\frac{5 x - 2}{x + 8})

\int_{- 2}^{2} x^{2} 4 - x^{2} d x

5 x + 3 x

What is the derivative of-0.5x^2+64x-25 ?
The derivative of-0.5x^2+64x-25 is -x+64
What is the first derivative of-0.5x^2+64x-25 ?
The first derivative of-0.5x^2+64x-25 is -x+64