What is the derivative of (x^3/3+1) ?

The derivative of (x^3/3+1) is x^2

What is the first derivative of (x^3/3+1) ?

The first derivative of (x^3/3+1) is x^2

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\frac{d}{d x} (\frac{x ^{3}}{3} + 1)

x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (1) = 0

= x^{2} + 0

Simplify

= x^{2}

t \to 0 lim (\frac{t}{t ^{2} - t})

\frac{d}{d x} (x + 1 - e^{x})

\int 3 sin (x) d x

\frac{d}{d x} (2 x - x^{2} + 2 x^{3})

What is the derivative of (x^3/3+1) ?
The derivative of (x^3/3+1) is x^2
What is the first derivative of (x^3/3+1) ?
The first derivative of (x^3/3+1) is x^2