What is the derivative of 2x-x^2+2x^3 ?

The derivative of 2x-x^2+2x^3 is 2-2x+6x^2

What is the first derivative of 2x-x^2+2x^3 ?

The first derivative of 2x-x^2+2x^3 is 2-2x+6x^2

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\frac{d}{d x} (2 x - x^{2} + 2 x^{3})

2 - 2 x + 6 x^{2}

Solution steps

\frac{d}{d x} (2 x - x^{2} + 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 2 - 2 x + 6 x^{2}

\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 7)

\int arcsin (3 x) d x

\int csc^{3} (5 x) d x

x \to 0 lim (\frac{x ^{2} + 2 ∣ x ∣}{x})

\int \frac{- 4}{( x ^{2} + 16 )} d x

What is the derivative of 2x-x^2+2x^3 ?
The derivative of 2x-x^2+2x^3 is 2-2x+6x^2
What is the first derivative of 2x-x^2+2x^3 ?
The first derivative of 2x-x^2+2x^3 is 2-2x+6x^2